T(n) = 2T(n/4) + sqrt(n)
a=2, b=4. log_4 2 = 0.5.
n^0.5 vs f(n) = n^0.5.
They are equal. Case 2.
Answer: Theta(sqrt(n) * log n) or Theta(n^0.5 log n).
If T(n) = T(n/3) + T(2n/3) + n, is the tree depth uniform?
No.
One brand reduces by 1/3 (slower decay, deeper path), the other by 2/3.
The tree is lopsided. The depth ranges from log_3 n to log_(3/2) n.